A concave mirror of focal length 1.5m forms an image of an object placed at a distance of 40cm. Find the position and nature of the image.

According to the question;

Focal length (f) = -1.5m;

Object distance (u) = -40cm = 0.40m; (1m = 100 cm)

By mirror formula;

⇒

⇒

⇒ v = 0.5454m = 54.54cm (1m = 100 cm).

Since v = 54.54cm which is positive hence image is behind the mirror.

The image is formed at the distance of 54.54 cm behind the mirror and is virtual and erect.