Let me place on Number Line.

Let the point O represent 0 on the number line.

We place a point A on the number line such that OA = 1 units.

Now, we draw AB perpendicular to OA at point A such that AB = 1unit.

By Pythagoras’ Theorem, we know that,

OB² = OA² + AB²

⇒ OB² = 1 + 1 = 2

⇒ OB = √2

Now, we draw BC perpendicular to OB at point B such that BC = 1unit.

Again, by Pythagoras’ Theorem, we know that,

OC² = OB² + BC²

⇒ OC² = 2 + 1 = 3

⇒ OC = √3

Now, taking O as a centre and OC as the radius, an arc is drawn which intersects the number line at P.

∴ OP = √3 units

Hence, Point P represents √3