An object is placed 10 cm away from a convex lens. The focal length of the lens is 40 cm, calculate the position and nature of the image.
Given
The distance of object from lens = -10cm (since the object is on the left-hand side of lens and acc. To our sign convention)
Focal length of convex lens = + 40cm (focal length of convex length is positive)
The distance of image from Lens = ?
Formula Used
Lens Formula
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Magnification formula
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Using lens formula
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V =
= -13.33cm
Hence, the image is on the same side of object at the distance of 13.33 cm from lens and the image is virtual.
Using magnification formula
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M = 1.33
The image is 1.33 times the object and is erect.
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