A block of 8 kg is moving with speed of 4 m/s on a frictionless surface. The block into the rest position by compressing the spring. The spring constant is 2 x 102 N/m. How much will the spring compressed?
Mass of the block (m) = 8 Kg
Velocity of the block (v) = 4m/s
Spring constant (k) = 2 × 102 N/m
The kinetic energy of the block will be converted into the potential energy of the spring.
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x = √0.64
x = 0.8 m
Hence, the compression of the spring is 0.8 m.
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