Find the value of current I in the circuit given below:

Resistors across AC and DE are in parallel i.e. RAC and RDE are in parallel.
So
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⇒ ![]()
⇒ ![]()
⇒ ![]()
Now R’p and RBC are I series.
R’s = R’p + RBC
⇒ R’s = 15 + 15 = 30Ω.
Again, RAB and R’s are in parallel.
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⇒ ![]()
⇒ R’’p = ![]()
Equivalent resistance of the above circuit is 10Ω.
Now, current flowing through the circuit is
I = ![]()
The value of current is 0.3A
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