In the adjoining figure, if O is centre of circle and BC is the diameter then the value of x is

In ΔABO, 2∠BAO + ∠BOA = 180
⇒ ∠BOA = 80°
⇒ ∠AOC = 180 – 80 = 100
By the theorem:-
The angle formed at the centre of a circle by an arc, is double of the angle formed by the same arc at any point on circle.
⇒ ∠AOC = 2x
⇒ x = 50°
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