A cooperative society of fisherman implemented such an improved plan for the production of fishes that the production in a year will be increased 10% in comparision to its previous year. In the present year if the cooperative society can produce 406 quintals of fishes, let us write by calculating, what will be the production of fishes after 3 years.
We know that population after n year ![]()
Where p = present population, r% = rate of increase in population in one year and n = number of years.
Given p = 406 quintals = 40600 kg [∵ 1 quintal = 100 kg], r% = 10% and n = 3 years
⇒ Production of fishes after 3 years ![]()
![]()
= 54038.6 kg
∴ Production of fishes after 3 years will be 54038.6 kg or 504.386 quintals.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.