Q11 of 25 Page 276

I have drawn an isosceles triangle ABC whose included angle of two equal sides is ∠ABC=45°; the bisector of ∠ABC intersects the side AC at the point D let us determine the circular values of ∠ABD, ∠BAD, ∠CBD and ∠BCD.


∠ABC = 45°




∵ BD is the angle bisector of ∠ABC



∠BAD + ∠ABC+ ∠BCD = π


∵ ABC is an isosceles triangle


⇒ ∠BAD = ∠BCD = x






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