Let us determine the volume of the cone when, (i) base area is 1.54 sq. m and height is 2.4m (ii) the length of base diameter is 21m and slant height is 17.5m.
i) Base area, πr2 = 1.54 sq.m.
height, h = 2.4 m
∴ volume of the cone,
= πr2 × h/3 m3
= 1.54 × 2.4/3 m3
= 1.232 m3
ii) base diameter = 21 m
∴ base radius, r = 21/2 = 10.5 cm
Slant height, l = 17.5 m
∴ height, h = √(l2 – r2) = √(17.52 – 10.52) = √(306.25 – 110.25) = √196 = 14 m
∴ volume of the cone,
= πr2h/3
= 22/7 × 10.52 × 14/3
= 1617 m3
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