Q3 of 10 Page 46


From the above equation calculate the amount of carbon dioxide in grams liberated by heating 25 g of calcium carbonate.

From the above equation, one mole of calcium carbonate (CaCO3) produces one mole of carbon dioxide (CO2).


Molar mass of CaCO3 = 40 + 12 + 3×16


= 100g


Molar mass of CO2 = 12 + 2×16


= 44g


Number of moles of CaCO3 =


=


= 0.25 moles


Now, 0.12 moles of CaCO3 produces 0.12 moles of CO2.


So the amount of carbon dioxide in grams liberated by heating 25 g of calcium carbonate = 0.25×44


= 11 g


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