Suppose P has coordinates (10,2) in a coordinate system X ’OX−Y ’OY and (−3,−6) in another coordinate system X1’O1X1↔ Y1’O1Y1? with X ’OX ║ X1’O1X1. Determine the coordinates of O with respect to the system X1’O1X1↔ Y1’O1Y1.
Given coordinate of P(x, y) = (10,2)
Coordinates of P with respect = (-3,-6)
toX1’O1X1↔ Y1’O1Y1(x’, y’)
to find, a & b
As we know, x = a + x’
10 = a - 3
a = 10+3
a = 13
similarly,
y = b + y’
2 = b - 6
b = 2+6
b = 8
So, Coordinates of O1 = (13, 8)
⇒ Coordinates of O With respect to O1 = (-13, -8)
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