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Now note that a common factor of p + 2q and q is also a factor of (p + 2q)−2⋅q = p, therefore must be 1.
Also a common factor of p + 2q and p + q is a factor of both (p + 2q) − ( p + q) = q and 2⋅(p + q) − ( p + 2q) = p hence must be 1.
Hence it is in its lowest form.
Couldn't generate an explanation.
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