Q1 of 12 Page 23

Find:
i. 81^1/2

ii. 64^1/6

iii. (125)^1/3

i. 81^1/2

Since, 81 = 9²

Using (aⁿ)^m = a^mn

= 9

Thus = 9

ii. 64^1/6

Since, 64 = 2⁶

Using (aⁿ)^m = a^mn

= 2

Thus = 2

iii. (125)^1/3

Since, 125 = 5³

Using (aⁿ)^m = a^mn

= 5

Thus = 5

Rationalise the denominators of the following:

ii.

iii.

If where a and b are rational then find the values of a and b.

Find:

i. 4^3/2

ii. 32^2/5

iii. 16^3/4

Simplify:

i. 2^2/3 .2^1/7

ii.

Questions · 12

2. Number System

1 2 3 4 5 1 2 3 1 2 3 4

Find:i. 811/2ii. 641/6iii. (125)1/3