Solve the following examples.
When a substance having mass 3 kg receives 600 cal of heat, its temperature increases by 10 °C. What is the specific heat of the substance?
Given data:
● Mass of substance = 3 kg
● Heat energy received = 600 cal
● Increase in temperature = 10°C
Calculation:
Relation between the heat energy given to the body, its mass, its specific heat capacity and rise in temperature is as follows.
Q = m×c×∆T
● m = mass of a substance
● the c = specific heat capacity of a substance
● ∆T = change in temperature
Or
Substitute the given values in the above equation.
= 0.2 cal g-10C-1
Specific heat of substance is 0.2 cal g-1°C-1.
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