Q4 of 25 Page 79

Find three consecutive whole numbers whose sum is more than 45 but less than 54.

let the lowest number be , so other numbers are x + 1

And x + 2


According to given conditions 45 < x + (x + 1) + (x + 2) < 54


Solving this equation, we have 45 < 3x + 3 < 54


Adding – 3 on both sides


42 < 3x < 51


Dividing by 3 on both sides


14 < x < 17


So x = 15 or x = 16


So consecutive numbers are 15,16,17 or 16,17,18


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