Two ships are there in the sea on either side of a lighthouse in such a way that the ships and the lighthouse are in the same straight line. the angles of depression of two ships as observed from the top of the lighthouse are 60° and 45°. If the height of the lighthouse is 200 m. Find the distance between the two ships
The figure is given below:

Let the distance between the foot of light house (O) to 1st ship(A) be x m
and the distance between lighthouse(O) & 2nd ship(B) be y m.
From figure;
∠ CAO = 60°
∠ CBO = 45°
Using trigonometry;
tan 60° = √3
![]()
![]()
Also, tan 45° = 1
![]()
y = 200
AB = OA + OB
![]()
AB = 200 + 115.47 = 315.47 m
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.