Prove that: log (1 + 2 + 3) = log 1 + log 2 + log 3

We know that 1 × 2 × 3 = 1 + 2 + 3 = 6

And we also know that log a + log b = log (ab)

So, log (1 × 2 × 3) = log 1 + log 2 + log 3

And we can say that log (1 + 2 + 3) = log 1 + log 2 + log 3

As log (1 × 2 × 3) = log (1 + 2 + 3)

log (1 + 2 + 3) = log 1 + log 2 + log 3

Hence, Proved.