Find the volume of CO₂ at NTP obtained on heating 10 g of 90% pure limestone.

Chemical Formula of Limestone is CaCO₃

Molecular Mass of Calcium Carbonate = 100 g/mol

10 grams of 100% pure of CaCO₃ = 10gm of CaCO₃

90% pure CaCO₃ means, it will contain = of CaCO₃

= 9 gm of CaCO₃

Number of moles of CaCO₃ =

=

= 0.09 mol

Now,

The reaction is given as follows:

Now according to the above reaction,

1 mole of CaCO₃ gives 1 mole of CO₂

So, 0.09 moles of CaCO₃ will give 0.09 moles of CO₂

Now according to the mole concept,

1 mole of CO₂ will occupy 22.4 L by volume.

So, 0.09 moles of CO₂ will occupy 22.4 × 0.09 L by volume

So total volume occupied = 2.016 L