If 2^x = 3^Y = 6^Z then show that .

• Given: 2^x = 3^y = 6^z

• To prove:

Now,

Let 2^x = 3^y = 6^z = k (where k is any constant)…(1)

From equation 1, we get

…(2)

…(3)

…(4)

Multiplying equation 2 and 3 we get

(∵ a^maⁿ = a^{m + n})

But, From(4)

Substituting in the above equation, we get

Hence Proved.