In an exam 80% of the students passed in Eng, 85% in Math and 75% in both. If 40 students failed in both subjects. What is the total number of students?
Formula:- n(A∪B) = n(A) + n(B) - n(A∩B)
Let x be total number of student
Given:-
n(A) = number of students pass in English ![]()
n(B) = number of students pass in math ![]()
n(A∩B) = number of students pass in both ![]()
40 = number of students falied in both subject .
n(A∪B) = n(A) + n(B) - n(A∩B)
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So, number of students failed in both either math or english = x - n(
)
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x = 400
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