Find the area of the parallelogram whose diagonals are :

and

Given two diagonals of a parallelogram are and

Let and

Recall the area of the parallelogram whose diagonals are given by the two vectors and is where

Here, we have (a₁, a₂, a₃) = (2, 3, 6) and (b₁, b₂, b₃) = (3, –6, 2)

Recall the magnitude of the vector is

Now, we find.

Thus, area of the parallelogram is 24.5 square units.