A man weighing 60 kg runs along the rails with a velocity of 18 km/h and jumps into a car of mass 1 quintal standing on the rails. Calculate the velocity with which the car will start travelling along the rails. (1 quintal=100kg).
Mass of man = 60kg = m1
Mass of car = 1 quintal = 100kg = m2
Initial velocity of man = 18km/hr = u1
(As, 1km = 1000m and 1hr = 3600s
18km/hr = 
= 5m/s )
Final velocity of man = v = v1
Initial velocity of car = 0m/s = u2
Final velocity of car = v = v2
v1 = v2 = v as the final velocity is combined for both man and car.
As the momentum is conserved.
According to Law of Conservation of Momentum
m1u1 + m2u2 = m1v1 + m2v2
60kg × 5m/s + 100kg × 0m/s = 60kg × v +100kg × v
300kgm/s + 0kgm/s = 60v + 100v
300kgm/s = 160v
300/160 = v
1.875m/s = v
Final velocity of both man and car = 1.875m/s
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.