A train is travelling at a speed of 90 kmhr^-1. Brakes are applied so as to produce a uniform acceleration of -0.5 ms^-2. Find how far the train will go before it is brought to rest?

Given: Speed of Train = 90kmhr^-1

Acceleration = -0.5ms^-2

To Find: Distance Covered before coming to rest

From the above statement, we can infer that:

Final Speed = 0 ms^-1

Here acceleration has a negative sign since it decreases the speed (retardation).

Now, Initial Speed = u = 90 kmhr^-1

Converting the initial speed into SI system:

1 km = 1000 m

1 hr = 60 minutes

1 minute = 60 seconds

So, 1 hr = 60 × 60 seconds = 3600 seconds

So,

Also, Final Speed = 0 ms^-1

From the equations of motion we know that,

Hence, distance covered by the train before coming to rest is 625 m.