A motor boat whose speed is 18 km/hr in still water takes 1hr more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream.
OR
A train travels at a certain average speed for a distance of 63 km and then travels at a distance of 72 km at an average speed of 6 km/ hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original average speed?
Let Speed of the stream be x km/h
Formula Used:![]()
Speed = Speed of boat in still water - speed of stream
Speed = (18 - x) km/h
Distance = 24 km
Going Downstream:
Speed = Speed of boat in still water + speed of stream
Speed = (18 + x) km/h
Distance = 24 km
According to the question,
Time taken Upstream = Time taken downstream + 1hr
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⇒ x2 + 48x – 324 = 0
⇒ x2 + 54x – 6x – 324 = 0
⇒ x(x + 54) – 6(x + 54) = 0
⇒ (x – 6)(x + 54) = 0
⇒ X = 6 or – 54
Since “x” is the time, it has to be non negative
∴ x = 6 km/h
So, the speed of the stream is 6km/h
OR
Let Original Average Speed be x km/h

According to the question, the total time taken is 3 hrs
⇒ ![]()
⇒ ![]()
⇒ 3x2 – 117x – 378 = 0
⇒ x2 – 39x – 126 = 0
⇒ x2 – 42x + 3x – 126 = 0
⇒ x(x – 42) + 3(x – 42) = 0
⇒ (x + 3)(x – 42) = 0
⇒ x = – 3 or 42
As “x” is speed, it has to be non negative
∴ x = 42 km/h
So, the original average speed is 42 km/h.
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