Find the probability of a non-leap year having 53 Sundays.
1 year = 365 days
And a year has 52 weeks
So 52 × 7= 364 days
So now remaining 1 day can be any day i.e. Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday
So P(probability of a non-leap year having 53 Sundays) = ![]()
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