Equation of the diameter of the circle x2 + y2 – 2x + 4y = 0 which passes through the origin is
Given that we need to find the equation of the diameter if the circle x2 + y2 - 2x + 4y = 0 which passes through origin.

We know that for a circle x2 + y2 + 2ax + 2by + c = 0
⇒ Centre = (- a, - b)
⇒ Radius = ![]()
For x2 + y2 - 2x + 4y = 0
⇒ Centre(C1) = ![]()
⇒ C1 = (1, - 2)
We know that the diameter of the circle passes through the centre.
We need to find the equation of the diameter passing through the points (1, - 2) and (0,0)
We know that the equation of the straight line passing through the points (x1,y1) and (x2,y2) is ![]()
⇒ ![]()
⇒ ![]()
⇒ y = - 2x
⇒ 2x + y = 0
∴The correct option is (c)
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