If tanA + tanB =A And CotA + CotB =B, prove that: cot(A +B) = 1/a – 1/b.
Given tanA + tanB =A And cotA + cotB =B
Consider cotA + cotB =B
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Then,
RHS ![]()

![]()
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We know that ![]()
= cot(A +B) = LHS
Hence, proved.
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