Find the sum of the following series to n terms:
1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + ………
The nth term be ![]()
Where
= (n - 0) + (n - 1) + (n - 2) + …… + (n - n)


Since,

………(1)
1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + ………….=![]()
From (1)
1 + (1 + 2) + (1 + 2 + 3) + (1 + 2 + 3 + 4) + ………..![]()
Thus, solving ![]()


Solving ![]()
We know by property that:
∑axn + bxn - 1 + cxn - 2…….d0=a∑xn + b∑xn - 1 + c∑xn - 2…….. + d0∑1
Thus,

We know,


Substituting

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Thus the answer is ![]()
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