A die is thrown. Find the probability of getting:
(i) a prime number
(ii) 2 or 4
(iii) a multiple of 2 or 3
given: die is thrown
Therefore, the total number of outcomes is six
n(S)=6
formula: ![]()
(i) let E be the event of getting a prime number
E= {2,3,5}
n(E)=3
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(ii) let E be the event of getting 2 or 4
E= {2,4}
n(E)=2
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(iii) let E be the event of getting a multiple of 2 or 3
E= {2,3,4,6}
n(E)=4
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