Find the area bounded by the curves
and x-axis.
OR
Find the area of the region.
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The given curves are,
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2y+3=x … (2)
Solving (1) and (2) we get,
2y +3 = y2
⇒ y2 – 2y – 3 =0
⇒ y2 – 3y + y – 3 =0
⇒ y(y – 3) + 1(y – 3) = 0
⇒ (y + 1)(y – 3) = 0
⇒ y = –1, 3
As y >0
So, y = 3
Substituting y = 3 in (2) we get,
x = 2(3) + 3
⇒ x = 9
So, (1) and (2) intersect at (9, 3)




= (9+9) – 9 = 9 sq. units
So, required area = 9 sq. units.
OR
The given curves are,
x2 + y2 = 8 … (1)
x2 = 2y … (2)
Solving (1) and (2) we get,
2y + y2 – 8 =
⇒ y2 + 2y – 8 = 0
⇒ y2 + 4y – 2y – 8 = 0
⇒ y(y + 4) – 2(y + 4) = 0
⇒ (y + 4)(y – 2) = 0
⇒ y = – 4, 2
But y > 0 hence, y = 2
Put y = 2 in (2) we get,
x2 = 4
⇒ x = + 2, – 2
So, the point of intersections are (-2, 2) and (2, 2).

So, required area =


As,![]()
So, ![]()

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Hence,![]()
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