Two lamps, one rated 100 W at 220 V and the other 200 W at 220V are connected (i) in series and (ii) in parallel to main electric supply of 220V. Find the current drawn in each case.
Given:
Voltage Rating of both lamps, V = 220 V
The power rating of first Lamp, P1 = 100 W
Power Rating of the second lamp, P2 = 200 W
To find: Current drawn in each case
Solution:
![]()
![]()
![]()
= 484 ohms
![]()
![]()
![]()
= 242 ohms
For series resistance, we know that equivalent resistance is given by,
Req = R1 + R2
= 242 + 484
= 726 ohms
So by Ohm’s Law we know that,
V = I× Req
I = V / Req
![]()
I = 0.3 A
For parallel connection, the equivalent resistance (Req) is given by,
![]()
![]()
![]()
![]()
Req = 161.33 ohms
So by Ohm’s Law we know that,
V = IReq
I = V / Req
I = 220 / 161.33
I = 1.36 A
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
