Prove that the tangent drawn at the mid-point of an arc of a circle is parallel to the chord joining the end points of the arc.

Given:
Let us draw a circle in which AMB is an arc and M is the midpoint of the arc AMB. Joined AM and MB. Also, TT' is a tangent at point M on the circle.
To Prove: AB || TT'
Proof:
As M is the midpoint of Arc AMB
Arc AM = Arc MB
AM = MB [As equal chords cuts equal arcs]
ABM = BAM [Angles opposite to equal sides are equal] [1]
As we know angle between tangent and the chord equals angle made by the chord in alternate segment,
So,
BMT' = BAM [2]
From [1] and [2]
ABM = BMT'
So, AB || TT' [two lines are parallel if the interior alternate angles are equal]
Hence Proved!
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