An electric oven of 2 kW power rating is operated in a domestic electric circuit (220 V) that has a current rating of 5 A. What result do you expect? Explain.
We will first calculate the Current drawn by the oven,
Given, Power(P)= 2kW
= 2x 1000 W
= 2000 W
Voltage(V)= 220V
We know P= V x I
Therefore the current drawn(I)=
= 9 A
The Current drawn by the electric oven is 9 Amperes which is high as compared to the fuse in the electric circuit which is of only 5 Amperes as a result the fuse will blow off cutting of the power supply when the electric oven will operate.
Given, Power(P)= 2kW
= 2x 1000 W
= 2000 W
Voltage(V)= 220V
We know P= V x I
Therefore the current drawn(I)=
= 9 A
The Current drawn by the electric oven is 9 Amperes which is high as compared to the fuse in the electric circuit which is of only 5 Amperes as a result the fuse will blow off cutting of the power supply when the electric oven will operate.
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