If
and I is the identity matrix of order 2, show that 
We know that I 
Now, LHS = I + A 
=
And on RHS = (I – A)



As we know,
cos 2θ = 1 - 2 sin2 θ
cos θ = 2 cos2 θ - 1
and sin2θ = 2 sinθ cosθ

As tanθ = sinθ/cosθ

=
= LHS
Hence Proved.
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