If
, find the value of λ so that A2 = λA – 2I. Hence, find A – 1.
A = ![]()
A2 = ![]()
= ![]()
Now, A2 = λA – 2I
= λA = A2 + 2I
= ![]()
= λ![]()
= ![]()
=
= 3 or λ = 1
So, A2 = A – 2I
Multiply by A – 1 both sides
= A.A. A – 1 = A. A – 1 – 2I. A – 1 = 0
= 2A – 1 = ![]()
Hence, A – 1 = ![]()
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