Q19 of 25 Page 8

Using integration, find the area of the region bounded by the following curves, after making a rough sketch: y = 1 + |x + 1|, x = -3, x = 3, y = 0.


Given; y = 1 + |x + 1|, x = -3, x = 3, y = 0


Area of the region bounded by the curve y=f(x), the x-axis and the ordinates x=a and x=b, where f(x) is a continuous function defined on [a,b], is given by .


Required Area





= −4 + 4 + 6 + 2 = 8


More from this chapter

All 25 →
17

Find the area of the region {(x, y): 0 ≤ y ≤ x2 + 1, 0 ≤ y ≤ x + 1, 0 ≤ x ≤ 2}.

 18

Find the area of the smaller region bounded by the ellipse and the line .

 20

Using integration, find the area of the triangle formed by the positive x-axis and tangent and normal to the circle x2 + y2 = 4 at (1, √3).

 21

If the area bounded by the parabola y2 = 16ax and the line y = 4kx is sq unit, then using integration find the value of k.