Q19 of 30 Page 9

Solve: 2yx/y dx + (y – 2x ex/y)dy = 0

Given: 2yx/y dx + (y – 2x ex/y)dy = 0


Explanation:


Rearranging the equation, we get,



Now, let us put x = vy


Differentiating, we get,



Therefore, the equation becomes,





2yevdv = - dy



Now, integrating both sides, we get,



2ev = - log|y| + log C



Hence, is the solution of the given differential equation.


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