For a CE-transistor amplifier, the audio signal voltage across the collector resistance of 2 k
is 2 V. Suppose the current amplification factor of the transistor is 100, find the input signal voltage and base current, if the base resistance is 1 k
.
The input signal voltage can be written as,
Vin = IBRB
Where,
IB is the base current ,
RB is the base resistance.
And we have,
β = IB / Ic
Where,
β is the current amplification factor ,
Ic is the collector current.
Given,
Collector resistance, Rc = 2 kΩ
Output voltage, V0 = 2 V
Base resistance, RB = 1 kΩ
Current amplification factor, β = 100
Thus,
we have base current ,
IB = VC / RCβ
⇒ IB =
= 10 μA and
Input voltage as:
Vin = IBRB
⇒ Vin = 1000 Ω × 10 × 10-6 A
⇒ Vin = 10-2 V = 10 mV.
The base current is 10 μA and input voltage is 10 mV.
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