The radii of the circular ends of a bucket of height 15 cm are 14 cm and r cm (r < 14 cm). If the volume of the bucket is 5390 cm3, then find the value of r. [Use π =
](CBSE 2011)
The bucket is in the shape of a frustum of a cone.
Given: h(height) =15cm
R(larger) =14cm
r(smaller)= r cm(assume)
Volume of frustum of cone =
cm3 (given)
⇒ 
⇒
⇒r2 + 14r + 196=343
⇒ r2 + 14r + 196-343=0
⇒ r2 + 14r-147=0
⇒ r2 + 21r-7r-147=0
⇒ r(r + 21) -7(r + 21)=0
⇒ (r-7)(r + 21)=0
There are two values of r possible r = 7 and r = -21
r=-21(neglected as negative value of r is not possible)
∴ r=7cm.
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