Q25 of 34 Page 176

The area of the region bounded by the curve x2 = 4y and the straight line x = 4y – 2 is.

Given;

The curve x2 = 4y and the straight line x = 4y – 2



By substituting for 4y;


⇒ x = x2 − 2


⇒ x2 − x − 2 = 0


⇒ (x + 1) (x − 2) = 0


∴ x = −1, 2.


Required area





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