If x = a cos θ + b sinθ and y = asinθ – bcosθ, show that:

As x = acos θ +bsinθ …(1)
Differentiating x w.r.t θ we get-
![]()
⇒ ![]()
⇒
…(2)
Similarly we have,
y = a sinθ – b cosθ …(3)
Differentiating y w.r.t θ we get-
![]()
⇒ ![]()
⇒ ![]()
⇒
…(4)
By chain rule we can write that:
![]()
From equation 2 and 4 we have-
![]()
From equations 1 and 3, we get-
…(5)
⇒ ![]()
Differentiating both sides w.r.t x –
![]()
Using product rule of differentiation, we can write it as-
⇒ ![]()
⇒ ![]()
From equation 5 we can write it as-
![]()
⇒ ![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

