A diet is to contain at least 80 units of Vitamin A and 100 units of minerals. Two food 
and 
are available costing ₹ 5 per unit and ₹ 6 per unit respectively. One unit of food 
contains 4 units of vitamin A and 3 nits of minerals whereas one unit of food 
contains 3 units of vitamin A and 6 units of minerals. Formulate this as a linear programming problem. Find the minimum cost of diet that consists of mixture of these two foods and also meets the minimum nutritional requirement.
let x units of F1 and y units of F2 be mixed. Therefore, we have to minimize the cost C = 5x + 6y
Now according to the given conditions, the equations are
4x + 3y≥80
3x + 6y≥100
x≥0, y≥0
Solving the equations to get the points of intersection
From the graph, we can see that the common area is on and beyond the points a, b and d
Now finding the cost
From the above equations, we can see that the minimum occurs at point b with the cost of 124
Therefore, number of units are
F1 = 12
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