Q8 of 12 Page 13

In a game, a man wins ₹ 5 for getting a number greater than 4 and loses ₹ 1 otherwise, when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a number greater than 4. Find the expected value of the amount he wins/loses.

OR


A bag contains 4 balls. Two balls are drawn at random (without replacement) and are found to be white. What is the probability that all balls in the bag are white?[CBSE 2016]

Given: a man wins Rs. 5 for getting a number greater than 4 and loses Rs. 1 otherwise


To find: the expected value of the amount he wins/loses if he throws dice thrice


Let S be the success of getting number greater than 4 and F be the failure of getting number less than or equal to 4


As he quit as and when he gets a number greater than 4 i.e. S


Then sample space will be {S, FS, FFS, FFF}


Case 1: E1: gets success i.e. number greater than 4 on 1st throw



{ Favorable outcomes = {5, 6} = 2 &


Total outcomes = {1, 2, 3, 4, 5, 6} = 6}


He wins Rs 5


Case 2: E2: gets failure i.e. number less than or equal to 4 on 1st throw and gets success i.e. number greater than 4 on 2nd throw



He wins Rs 5 and loses Rs. 1


Amount = 5 – 1 = Rs. 4


Case 3: E3: gets failure 1st throw, gets failure on 2nd throw and gets success on 3rd throw



He wins Rs 5 and loses Rs. 2


Amount = 5 – 2 = Rs. 3


Case 4: E4: gets failure 1st throw, gets failure on 2nd throw and gets failure on 3rd throw



He loses Rs. 3


Amount = Rs. -3





Hence, expected value of prize he wins/loses, E(X),



OR


Given: A bag contains 4 balls


To find: probability that all balls in the bag are white


Formula used:


Bayes’ Theorem:


Given E1, E2, E3....En are mutually exclusive and exhaustive events, we can find the conditional probability P(Ei|A) for any event A associated with Ei as follows:



Two balls are drawn at random (without replacement) and are found to be white. This means at least two balls are white


Now,


Let A: Two drawn balls are white


E1: All the four balls are white


E2: Three balls are white


E3: Two balls are white


Since E1, E2, E3 are mutually exclusive and exhaustive events






Probability that all the balls are white is given by, P(E1|A)









Hence, probability that all balls in the bag are white is 0.6

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