Prove that the tetrahedron with vertices at the points O(0, 0, 0), A(0, 1, 1), B(1, 0, 1) and C(1, 1, 0) is a regular one.
Given: Points are O(0, 0, 0), A(0, 1, 1), B(1, 0, 1) and C(1, 1, 0)
To prove: given points are forming a regular tetrahedron
All edges of a regular tetrahedron are equal
Formula used:
The distance between any two points (a, b, c) and (m, n, o) is given by,
![]()
Therefore,
Distance between O(0, 0, 0) and A(0, 1, 1) is OA,
![]()
![]()
![]()
![]()
Distance between O(0, 0, 0) and B(1, 0, 1) is OB,
![]()
![]()
![]()
![]()
Distance between O(0, 0, 0) and C(1, 1, 0) is OC,
![]()
![]()
![]()
![]()
Distance between A(0, 1, 1) and B(1, 0, 1) is AB,
![]()
![]()
![]()
![]()
Distance between B(1, 0, 1) and C(1, 1, 0) is BC,
![]()
![]()
![]()
![]()
Distance between A(0, 1, 1) and C(1, 1, 0) is AC,
![]()
![]()
![]()
![]()
Clearly,
AB = BC = AC = OA = OB = OC
All edges are equal
Thus, A, B, C and O forms a regular tetrahedron
Hence Proved
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.