The function f (x) = tanx – x
Given f (x) = tanx – x
Applying the first derivative we get
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Applying the sum rule of differentiation, so we get
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Applying the derivative,
⇒ f' (x)=sec2x-1
As square of any number is always positive,
So f’(x)>0 ∀ x∈R
Hence tan x –x is always increases.
So the correct option is option A.
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