Show that the triangle ABC with vertices A (0, 4, 1), B (2, 3, – 1) and C (4, 5, 0) is right angled.
Given; The vertices A (0, 4, 1), B (2, 3, – 1) and C (4, 5, 0).
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⇒ AC2 = AB2 + BC2
∴ Triangle ABC a right angled.
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