Q8 of 27 Page 11

Find the equation of the hyperbola with vertices at (0, ± 6) and e = 5/3.Find its foci.


Since the vertices are on the y- axes, the equation is of form ,


As vertices are (0, ± 6), a = 6


b2 = a2(e2 – 1)




= 64


So required equation is


Foci are (0, ±ae)


= (0, ±10)


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