Prove the following statement by contradiction method.
p: The sum of an irrational number and a rational number is irrational.
Let p be false.
It means the sum of an irrational and a rational number is rational.
Let r be a rational number.
Let √m is irrational, and n is rational number.
⇒ √m + n = r
⇒ √m = r – n
Now √m is irrational; whereas (r – n) is rational.
This is contradiction.
Hence our assumption was wrong.
∴ p is true.
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