Show that the following statement is true by the method of contrapositive.
p: If x is an integer and x2 is even, then x is also even.
Let q and r be the statements given by:
q: If x is an integer and x2 is even
r: x is an even integer.
Then, p: “If q, then r”.
If possible, let r be false. Then,
⇒ x is not an even integer.
⇒ x is an odd integer.
⇒ x = (2m + 1) for some integer m.
⇒ x2 = (2m + 1)2
⇒ x2 = 4m2 + 1 + 4m
⇒ x2 = 4m (m + 1) + 1
⇒ x2 is an odd integer.
⇒ q is false.
Thus, r is false
⇒ q is false.
Hence p: “If q, then r” is true statement.
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