If the highest common factor of numbers 408 and 1032 is expressed in the form of 1032x – 408 × 5, then find the value of x.
If the HCF of 408 and 1032 can be written as
By Euclid’s division algorithm,
1032 = 408×2 + 216
408 = 216×1 + 192
216 = 192×1 + 24
192 = 24×8 + 0
Since the remainder becomes 0 here, so HCF of 408 and 1032 is 24
Now,
1032x - 408*5 = HCF of these numbers
⟹ 1032x - 2040 = 24
⟹ 1032x = 24 + 2040
⟹ x = 2064/1032
⟹ x = 2
So value of x is 2.
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